A) \[\frac{\pi }{60}rad/\sec \]
B) \[\frac{\pi }{30}rad/\sec \]
C) \[60\,\pi \,rad/\sec \]
D) \[30\,\pi \,rad/\sec \]
Correct Answer: B
Solution :
We know that second's hand completes its revolution \[(2\pi )\]in 60 sec \[\therefore \] \[\omega =\frac{\theta }{t}=\frac{2\pi }{60}=\frac{\pi }{30}\,rad/\sec \]You need to login to perform this action.
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