A) 6
B) 10
C) 12
D) 4
Correct Answer: B
Solution :
Using\[\theta ={{\omega }_{0}}t+\frac{1}{2}\alpha {{t}^{2}}\] ?.(ii) Given,\[\alpha =3.0\,rad/{{s}^{2}},{{\omega }_{0}}=2.0\,rad/s,t=2s\] Hence, \[\theta =2\times 2+\frac{1}{2}\times 3\times {{(2)}^{2}}\] or \[\theta =4+6=10\,rad\]You need to login to perform this action.
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