A) 0.43 eV
B) 1.10 eV
C) 1.36 eV
D) 2.47 eV
Correct Answer: B
Solution :
\[E=hv=\frac{hc}{\lambda }\]or \[\frac{E}{E'}=\frac{\lambda '}{\lambda }\] or \[\frac{E}{1.23}=\frac{10,000}{5,000}\]or \[E=2.46\,eV\] Now, \[hv-W=\frac{1}{2}m{{({{v}_{\max }})}^{2}}\]or \[hv-W=e{{V}_{s}}\] \[2.46\,eV-W=e(1.36)\]volt or \[W=(2.46-1.36)=1.1\,eV\] Hence, the correction option is .You need to login to perform this action.
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