A) 2
B) 4
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
The speed of photon\[=c=3\times {{10}^{8}}\,m/s,\] Wavelength of photon is v. Wavelength of electron \[=\frac{h}{mv}.\] Now, \[\frac{\text{KE}\,\text{of}\,\text{electron}}{\text{KE}\,\text{of}\,\text{photon}}=\frac{\frac{1}{2}m{{v}^{2}}}{hv}=\frac{1}{2}\frac{m{{v}^{2}}}{hc}\lambda =\frac{m{{v}^{2}}h}{2hcmv}\] \[=\frac{v}{2c}=\frac{1}{4}\,(\because \,v=c/2)\] Hence, the correction option is [d].You need to login to perform this action.
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