A) the wave nature of electron.
B) particle nature of electron.
C) Palli's exclusion behavior
D) None of these
Correct Answer: A
Solution :
\[mvr=\frac{nh}{2\pi }\] \[\therefore \] \[\frac{h}{mv}=\frac{2\pi r}{n}\] \[\frac{h}{mv}=de-\]Broglie wavelength. Hence, the correction option is .You need to login to perform this action.
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