A) \[60{}^\circ \]
B) \[30{}^\circ \]
C) \[45{}^\circ \]
D) \[50{}^\circ \]
Correct Answer: B
Solution :
At the polarizing angle \[{{i}_{p}}.\tan {{i}_{p}}=\mu =\sqrt{3}\] Now, \[\frac{\sin {{i}_{p}}}{\operatorname{sinr}}=\mu =\sqrt{3}\] \[\Rightarrow \]\[\sin r=\frac{\sin {{60}^{o}}}{\sqrt{3}}=\frac{1}{2}\]\[\therefore \]\[r={{30}^{o}}\] Hence, the correction option is [b].You need to login to perform this action.
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