A) 50 mA
B) 20 mA
C) 40 mA
D) 80 mA
Correct Answer: D
Solution :
\[{{D}_{2}}\]is reverse biased. As it is an ideal diode, its resistance is infinite and no current flows through it, \[{{D}_{1}}\]is forward biased. As it is an ideal diode, its resistance is zero and hence, the current through \[10\Omega \]resistor is \[I=\frac{2}{10+15}=0.08\,A=80\,mA\] Hence, the correction option is [d].You need to login to perform this action.
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