A) 1 : 5
B) 1 : 4
C) 1 : 2
D) 1 : 1
Correct Answer: C
Solution :
If E is the energy incident on photon and \[{{W}_{0}}\]the work function, then \[E-{{W}_{0}}=\]available energy \[E-{{W}_{0}}=\frac{1}{2}m{{v}^{2}}\]or \[v=\sqrt{2\left( \frac{E-{{W}_{0}}}{m} \right)}\] \[\because \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{1-0.5}{2.5-0.5}}=\sqrt{\frac{0.5}{2}}=\frac{1}{2}\] Hence, the correction option is [c].You need to login to perform this action.
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