A) one
B) two
C) three
D) four
Correct Answer: C
Solution :
Energy gained by electron \[=13.6-12.1=1.5\text{ }eV.\]The electron will jump to an orbit of principal Quantum number n given by \[13.6/{{n}^{2}}=1.5\] Or\[{{n}^{2}}=13.6/1.5=9\]or \[n=3.\] Hence, the possible transitions are \[n=3\]to \[n=2,\,n=3\]to n = 1 and n = 2 to n = 1. Thus three spectral Lines will be emitted. Hence, the correction option is [c].You need to login to perform this action.
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