NEET Sample Paper NEET Sample Test Paper-17

  • question_answer A man of mass m stands on a frame of mass M. He pulls on a light rope, which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope?

    A) \[\frac{1}{2}(M+m)g\]                      

    B) \[(M+m)g\]                 

    C) \[(M-m)g\]                   

    D) \[(M+2m)g\]

    Correct Answer: A

    Solution :

    Let T = tension in the rope = Force exerted by the nan on the rope = Force exerted by the rope on he man.      N = normal reaction between man and frame. For equilibrium, \[T+N=mg,\,T=N+Mg.\] Solving the above relations, we get, \[T=\frac{1}{2}(M+m)g\] Hence, the correction option is [a].

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