• # question_answer A man of mass m stands on a frame of mass M. He pulls on a light rope, which passes over a pulley. The other end of the rope is attached to the frame. For the system to be in equilibrium, what force must the man exert on the rope? A) $\frac{1}{2}(M+m)g$                      B) $(M+m)g$                 C) $(M-m)g$                   D) $(M+2m)g$

Let T = tension in the rope = Force exerted by the nan on the rope = Force exerted by the rope on he man.      N = normal reaction between man and frame. For equilibrium, $T+N=mg,\,T=N+Mg.$ Solving the above relations, we get, $T=\frac{1}{2}(M+m)g$ Hence, the correction option is [a].