A) \[{{H}_{2}}\]
B) \[He\]
C) \[C{{O}_{2}}\]
D) \[N{{H}_{3}}\]
Correct Answer: A
Solution :
\[dQ=n{{C}_{P}}dT\]or \[{{C}_{P}}=\frac{dQ}{ndT}=\frac{70}{ndT}=\frac{70}{2.5}=\frac{7}{2}(R)\] i.e., the gas is diatomic or it is\[{{H}_{2}}\] Hence, the correction option is [a].You need to login to perform this action.
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