A) \[\frac{{{F}^{2}}}{K}\]
B) \[\frac{2{{F}^{2}}}{K}\]
C) \[\infty \]
D) \[\frac{{{F}^{2}}}{2K}\]
Correct Answer: B
Solution :
For maximum positive work the final speed must be zero. Let the extension in the spring be 1. Applying work-energy theorem on the block, we get\[F\ell -\frac{1}{2}k{{\ell }^{2}}=0\] \[\ell =\frac{2F}{k}\]or work done \[=F\ell =\frac{2{{F}^{2}}}{k}\] Hence, the correction option is [b].You need to login to perform this action.
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