A) 1000 V
B) 2000V
C) 4000V
D) 8000V
Correct Answer: D
Solution :
Instantaneous induced emf is \[e=nAB\omega \sin \omega t\] Peak value \[{{e}_{0}}\]of e is obtained when cot is an integral multiple of \[\pi /2.\]Thus\[{{e}_{0}}=nAB\omega \] or \[{{e}_{0}}=2000\times 0.1\times 0.2\times 200=8000\,V.\] Hence, the correction option is (d).You need to login to perform this action.
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