A) \[~{{10}^{4}}W\]
B) 10 W
C) 2.5 W
D) 5 W
Correct Answer: C
Solution :
Voltage amplitude \[{{V}_{0}}=100V,\]current amplitude and phase difference between I and V is\[\phi =\frac{\pi }{3}={{60}^{o}}.\]Now power dissipated is given by \[P=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \Phi \frac{100\times 100\times {{10}^{-3}}}{2}\cos {{60}^{o}}=2.5\,W.\] Hence, the correction option is (c).You need to login to perform this action.
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