A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{3}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
According to the figure \[{{Q}_{1}}={{T}_{o}}{{S}_{o}}+\frac{1}{2}{{T}_{o}}{{S}_{o}}=\frac{3}{2}{{T}_{o}}{{S}_{o}}\] \[{{Q}_{2}}={{T}_{o}}(2{{S}_{o}}-{{S}_{o}})={{T}_{o}}{{S}_{o}}\] \[{{Q}_{3}}=0\] \[\therefore \]\[\eta =\frac{W}{{{Q}_{1}}}=\frac{{{Q}_{1}}-{{Q}_{2}}}{{{Q}_{1}}}=1-\frac{{{Q}_{2}}}{{{Q}_{1}}}=1-\frac{2}{3}=\frac{1}{3}\] Hence, the correction option is (c).You need to login to perform this action.
You will be redirected in
3 sec