A) 1.003 MHz and 0.997 MHz
B) 3001 kHz and 2997 kHz
C) 1003 kHz and 1000 kHz
D) 1 MHz and 0.997 MHz
Correct Answer: A
Solution :
Here, \[\upsilon =1\,MHz,\,\Delta v=3\,kHz=0.003\,MHz.\] Using amplitude modulation, the frequencies of the side band \[=(\upsilon +\Delta v)\]and \[(\upsilon -\Delta v)\] \[=(1+0.003)\]and \[(1-0.003)\] \[=1.003\,MHz\]and 0.997 MHz Hence, the correction option is (a).You need to login to perform this action.
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