A) V
B) \[\frac{1}{2}V\]
C) \[\frac{1}{3}\,V\]
D) \[\frac{2}{3}\,V\]
Correct Answer: C
Solution :
After steady state there will be no current through the capacitor. In steady state \[i=\frac{(2V-V)}{2R+R}=\frac{V}{3R}\] For \[{{V}_{ab}}:{{V}_{a}}+2iR-2V+V={{V}_{b}}\] \[\therefore \] \[{{V}_{a}}-{{V}_{b}}=V-2iR=V=\frac{V}{3}\] Hence, the correction option is [c].You need to login to perform this action.
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