A) \[\frac{2m{{v}_{0}}}{q{{B}_{0}}}\]
B) \[\frac{m{{v}_{0}}}{qB}\]
C) \[\frac{m{{v}_{0}}}{qB}\]
D) \[\frac{2m{{v}_{0}}}{q{{B}_{0}}}\]
Correct Answer: D
Solution :
Path of the particle is a circle. y = 2 (radius of circle) or diameter \[=\frac{2m{{v}_{0}}}{q{{B}_{0}}}\] Hence, the correction option is [d].You need to login to perform this action.
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