A) 14.45
B) 15.45
C) 16.45
D) 17.45
Correct Answer: C
Solution :
\[{{P}_{{{N}_{2}}}}=715-15=700\,mm\] \[V=55\,mL\] \[\therefore \] \[PV=\frac{w}{M}RT\] \[\frac{700}{760}\times \frac{55}{1000}=\frac{{{w}_{{{N}_{2}}}}}{28}\times 0.0821\times 300\] \[{{w}_{{{N}_{2}}}}=0.058\,g\] \[\therefore \]% \[{{N}_{2}}=\frac{0.058}{0.35}\times 100=16.45\]sYou need to login to perform this action.
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