A) \[C{{H}_{3}}CHO+HCN\xrightarrow{{}}C{{H}_{3}}CH(OH)CN\]
B) \[C{{H}_{3}}-CH=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{{{H}^{+}}}\]\[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
C)
D)
Correct Answer: D
Solution :
Nucleophile \[(-N{{H}_{3}})\] replaces other nucleophile (-Br) in the reaction.You need to login to perform this action.
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