A) \[\frac{\pi }{3}\]
B) \[\frac{2\pi }{3}\]
C) \[\pi \]
D) \[\frac{\pi }{6}\]
Correct Answer: B
Solution :
Phase difference\[=\frac{2\pi }{\lambda }\times \]path difference Path difference between two points, \[\Delta x=15-10=5\,m\] The period, \[T=0.05\,s\] \[\Rightarrow \]Frequency \[v=\frac{1}{T}=\frac{1}{0.05}=20\,Hz\] Velocity, \[v=300\,m/s\] \[\therefore \] Wavelength, \[\lambda =\frac{v}{v}=\frac{300}{20}=15\,m\] Hence, phase difference \[\Delta \phi =\frac{2\pi }{\lambda }\times \Delta x=\frac{2\pi }{15}\times 5=\frac{2\pi }{3}\]You need to login to perform this action.
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