A) \[6.25\times {{10}^{7}}\,N/C\]
B) \[9.28\times {{10}^{7}}\,N/C\]
C) \[13.1\times {{11}^{11}}\,N/C\]
D) \[20.5\times {{10}^{7}}\,N/C\]
Correct Answer: A
Solution :
By using \[E=9\times {{10}^{9}}.\frac{2pr}{{{({{r}^{2}}-{{l}^{2}})}^{2}}}\] Where\[p=(500\times {{10}^{-6}})\times (10\times {{10}^{-2}})=5\times {{10}^{-5}}\,c\times m,\] \[r=25cm=0.25\,m,\,l=5\,cm=0.05\,m\] \[E=\frac{9\times {{10}^{9}}\times 2\times 5\times {{10}^{-5}}\times 0.25}{{{\{{{(0.25)}^{2}}-{{(0.05)}^{2}}\}}^{\,2}}}\] \[=6.25\times {{10}^{7}}\,N/C\]You need to login to perform this action.
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