A) 400
B) 300
C) 200
D) 150
Correct Answer: A
Solution :
\[R=\frac{{{R}_{0}}}{{{2}^{{\scriptstyle{}^{t}/{}_{Th}}}}}\] \[100=\frac{1600}{{{2}^{{\scriptstyle{}^{t}/{}_{Th}}}}}\] \[{{2}^{t/Th}}={{2}^{4}}\] or \[{{T}_{h}}=\frac{t}{4}=\frac{8}{4}=2\sec \] \[R'=\frac{{{R}_{0}}}{{{2}^{{\scriptstyle{}^{t'}/{}_{Th}}}}}=\frac{1600}{{{2}^{{\scriptstyle{}^{4}/{}_{2}}}}}=400\]You need to login to perform this action.
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