A) \[\sqrt{3}\]
B) \[\frac{3}{2}\]
C) \[2\]
D) \[\sqrt{3}\]
Correct Answer: D
Solution :
As is clear from fig., \[A={{30}^{o}},\,\,{{i}_{1}}={{60}^{o}},\] As the ray retraces its path on reflection at the silvered face, therefore, \[{{i}_{2}}=0,\,\,{{r}_{2}}=0\] As \[{{r}_{1}}+{{r}_{2}}=A\] \[\therefore \] \[{{r}_{1}}+0={{30}^{o}}\] or \[{{r}_{1}}={{30}^{o}}\] \[\mu =\frac{\sin {{i}_{1}}}{\sin {{r}_{1}}}=\frac{\sin {{60}^{o}}}{\sin {{30}^{o}}}=\frac{\sqrt{3}/2}{1/2}=\sqrt{3}\]You need to login to perform this action.
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