A) \[1.2\,eV\]
B) \[0.98\,eV\]
C) \[0.45\text{ }eV\]
D) \[0\text{ }eV\]
Correct Answer: B
Solution :
\[K.{{E}_{\max }}=\frac{hc}{\lambda }-\phi \,\,=\frac{12400\,eV{{A}^{o}}}{5000{{A}^{o}}}-1.5\,eV\] \[=(2.48-1.5)\,eV\] \[=0.98\,eV\]You need to login to perform this action.
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