A) \[4\pi \]
B) \[3\pi \]
C) \[2\pi \]
D) \[\pi \]
Correct Answer: D
Solution :
\[e=M\frac{di}{dt}=0.005\times \frac{d}{dt}({{i}_{0}}\sin \omega t)=0.005\,{{i}_{0}}\,\omega \,\cos \,\omega t\] \[={{e}_{0}}\,\cos \,\omega t\] \[\therefore \] \[{{e}_{\max }}=0.005\times 2\times 100\pi =\pi \]You need to login to perform this action.
You will be redirected in
3 sec