A)
B)
C)
D)
Correct Answer: D
Solution :
Potential energy of particle performing SHM is given by: \[PE=\frac{1}{2}m{{\omega }^{2}}{{y}^{2}},\]i.e., it varies paraboli cally such that at mean position it becomes zero and maximum at extreme position.You need to login to perform this action.
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