A)
B)
C)
D)
Correct Answer: C
Solution :
Displacement, \[x=A\cos (\omega t)\](given) Velocity, \[v=\frac{dx}{dt}=-A\omega \sin (\omega t)\] Acceleration, \[a=\frac{dv}{dt}=-A{{\omega }^{2}}\cos (\omega t)\] Hence graph correctly depicts the variation of a with t.You need to login to perform this action.
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