A) \[\frac{1}{2}\]
B) \[\frac{3}{4}\]
C) \[\frac{7}{8}\]
D) \[\frac{14}{9}\]
Correct Answer: D
Solution :
Let the mass of solid sphere be M and when cavity is made, its mass \[M'=\frac{7M}{8}\] Then, \[{{F}_{1}}=\frac{GMm}{{{(2R)}^{2}}}=\frac{GMm}{4{{R}^{2}}}\] and \[{{F}_{2}}=\frac{G.\frac{7M}{8}m}{\frac{3{{R}^{2}}}{2}}=\frac{7}{8}\times \frac{4}{9}\,\,\frac{GMm}{{{R}^{2}}}\] \[\therefore \] \[\frac{{{F}_{2}}}{{{F}_{1}}}=\frac{14}{9}\]You need to login to perform this action.
You will be redirected in
3 sec