A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
According to Kepler's third law of planetary motion, \[{{T}^{2}}\propto {{R}^{3}}\] \[\therefore \] \[\left( \frac{{{T}_{A}}}{{{T}_{B}}} \right)={{\left( \frac{{{R}_{A}}}{{{R}_{B}}} \right)}^{3}}\] \[\Rightarrow \] \[{{(8)}^{2}}={{\left( \frac{{{R}_{A}}}{{{R}_{B}}} \right)}^{3}}\] \[\Rightarrow \] \[\frac{{{R}_{A}}}{{{R}_{B}}}=4\] \[\Rightarrow \] \[{{R}_{A}}=4{{R}_{B}}.\]You need to login to perform this action.
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