A) 4V
B) 2V
C) 12V
D) 6V
Correct Answer: B
Solution :
galvanometer show no deflection that implies no current passes through it potential different drop across \[{{\operatorname{R}}_{1}}=\] In series voltage divides while current is same in parallel current divide while voltage is same \[={{V}_{A}}\frac{{{R}_{1}}}{{{R}_{1}}+R}\] \[=12\times \frac{500}{\left( 500+100 \right)}=10V\] Potential different across R=12-10=2V \[{{\operatorname{V}}_{B}}\]=2V [R is parallel to upper circuit]You need to login to perform this action.
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