A) -G
B) \[-\frac{8G}{3}\]
C) \[-\frac{4G}{3}\]
D) -4G
Correct Answer: D
Solution :
gravitational potential \[=\frac{GM}{x}\] \[V=\left[ -\frac{GM}{1}-\frac{GM}{2}-\frac{GM}{4}-\frac{GM}{8}-........\infty \right]\] \[=-GM\frac{\left[ 1+\frac{1}{2}+\frac{1}{4}+........\infty \right]}{Geometric\,\,Progression}\] In geometric progression \[{{\operatorname{S}}_{n}}=\left[ \frac{1-{{r}^{n}}}{1-r} \right]\] \[=-20\left[ \frac{1}{1-\frac{1}{2}} \right]=-4G\]You need to login to perform this action.
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