A) Na
B) O
C) Cl
D) N
Correct Answer: A
Solution :
Na \[_{11}Na=I{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{1}}\] \[\operatorname{i}.e for last electron, l= 0\] \[\therefore m=0\]You need to login to perform this action.
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