A) 1:26
B) 1:20
C) 1:10
D) 1:15
Correct Answer: A
Solution :
\[\frac{{{\rho }_{FCC}}}{{{\rho }_{BCC}}}=\frac{{{Z}_{FCC}}}{{{\left( {{a}^{3}} \right)}_{FCC}}}\times \frac{{{\left( {{a}^{3}} \right)}_{BCC}}}{{{Z}_{BCC}}}\] \[=\frac{4\times {{\left( 3.0 \right)}^{3}}}{2\times {{\left( 3.5 \right)}^{3}}}=\frac{1}{26}=1:26\]You need to login to perform this action.
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