A) 200P
B) 400P
C) \[\frac{P}{200}\]
D) 100P
Correct Answer: A
Solution :
\[\lambda =\frac{h}{p} \left[ de Broglie wavelength \right]\] \[p=\frac{h}{\lambda }\] \[\frac{\Delta P}{P}=\frac{\Delta \lambda }{\lambda }\] \[\frac{P}{{{P}_{initial}}}=\frac{0.5}{100}\] \[{{P}_{initial}}=200\,\operatorname{P}\]You need to login to perform this action.
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