A) \[2\sqrt{3}W\]
B) \[\sqrt{3}W\]
C) \[\frac{\sqrt{3}}{2}W\]
D) \[\frac{\sqrt{3}}{4}W\]
Correct Answer: D
Solution :
\[\theta =0{}^\circ ,\,\,\,~{{\theta }_{2}}=6{{0}^{P}}\] \[\operatorname{W}=P{{E}_{1}}-P{{E}_{2}}\] \[= MB cos 0{}^\circ - MB cos60{}^\circ \] \[=MB-\frac{MB}{2}\] \[W=\frac{MB}{2}\] .....(1) \[\tau \left( \theta = 60{}^\circ \right) = MBSm60{}^\circ = \frac{\sqrt{3}}{2} MB\] using equation (1) in this we get \[\tau = \sqrt{3}\operatorname{W}\]You need to login to perform this action.
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