If electric field is given be \[E=\left( \frac{1}{{{X}^{2}}} \right)\uparrow V/m,\]the magnitude of potential difference between point \[X=10\text{ }cm\] and \[X=20\text{ }cm\] is
A) \[1\,V\]
B) \[2\,\,V\]
C) \[5\,\,V\]
D) \[10\,V\]
Correct Answer:
C
Solution :
As \[dV=-\int{E.dx=-\int_{0.1}^{0.2}{\frac{1}{{{x}^{2}}}\,dx=-5V}}\]