A) \[qE\]
B) \[2\,qE\]
C) \[\frac{qE}{2}\]
D) \[\frac{q\,E}{4}\]
Correct Answer: D
Solution :
Given, \[\varepsilon =\frac{q}{4\pi {{\varepsilon }_{0}}{{x}^{2}}}\] Hence, the magnitude of the electric intensity at a distance 2 x from charge q is \[E'=\frac{q}{4\pi {{\varepsilon }_{0}}{{(2x)}^{2}}}=\frac{q}{4\pi {{\varepsilon }_{0}}{{x}^{2}}}\times \frac{1}{4}=\frac{E}{4}\] Therefore experienced by a similar charge q at distance 2 x is \[F=qE'=\frac{qE}{4}\]You need to login to perform this action.
You will be redirected in
3 sec