A) 289
B) 89
C) 345
D) 189
Correct Answer: D
Solution :
According to Kohlrausch's law \[{{\wedge }^{o}}\left( SO_{4}^{2-} \right)=160\,S\,\,c{{m}^{2}}\,\,mo{{l}^{-1}}\] \[{{\wedge }^{o}}\left[ A{{l}_{2}}{{(S{{O}_{4}})}_{3}} \right]\,2\,{{\wedge }^{o}}\,\left( A{{l}^{3+}} \right)+3{{\wedge }^{o}}\left( SO_{4}^{2-} \right)\] \[{{\wedge }^{o}}\left[ A{{l}_{2}}{{(S{{O}_{4}})}_{3}} \right]\,=858\,S\,c{{m}^{2}}\,mo{{l}^{-1}}\] \[858=2{{\wedge }^{o}}\left( A{{l}^{3+}} \right)+3\times 160\] \[{{\wedge }^{o}}\left( A{{l}^{3+}} \right)=\frac{858-480}{2}=189\,S\,c{{m}^{2}}\,mo{{l}^{-1}}\]You need to login to perform this action.
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