A) \[1\times {{10}^{-10}}\]
B) \[29.5\times {{10}^{2}}\]
C) 10
D) \[1\times {{10}^{10}}\]
Correct Answer: D
Solution :
\[{{E}^{o}}_{cell}=\frac{0.0591}{n}\,\log \,{{K}_{C}}\] \[0.295=\frac{0.0591}{2}\log \,{{K}_{C}}\] \[\frac{0.590}{0.0591}=\log \,{{K}_{C}}\] \[{{K}_{C}}=1\times {{10}^{10}}\]You need to login to perform this action.
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