A) 140 kJ/mol
B) 150 kJ/mol
C) 43.44 kJ/mol
D) 100 kJ/mol
Correct Answer: A
Solution :
\[{{E}_{a}}=\frac{2}{3}\,\,\left[ {{E}_{{{a}_{1}}}}+{{E}_{{{a}_{2}}}}-{{E}_{{{a}_{3}}}} \right]\]You need to login to perform this action.
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