A) 200 mL
B) 156.4 mL
C) 170.4 mL
D) 190.4 mL
Correct Answer: C
Solution :
\[CrO_{4}^{-2}+{{S}_{2}}O_{3}^{-2}\xrightarrow{{}}SO_{4}^{-2}+Cr(O{{H}^{-}}){{~}_{4}}\] \[Eq.\,\,of\,\,CrO_{4}^{-2}=\,\,Eq.\,\,of\,\,{{S}_{2}}O_{3}^{-2}\] \[0.154\times 3\times V\,\,=\,\,0.246\times 8\times 40\] \[V\,\,=\,\,170.4\text{ }ml\]You need to login to perform this action.
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