A) \[6.63\times {{10}^{-7}}\]
B) \[6.63\times {{10}^{-31}}m\]
C) \[6.63\times {{10}^{-4}}m\]
D) \[6.63\times {{10}^{-35}}m\]
Correct Answer: B
Solution :
[b] \[6.63\times {{10}^{-31}}m\] According to de-broglie equation \[\lambda =\frac{h}{mv}--(1)\] \[m=10mg,V=100m/s,h=6.63\times {{10}^{-34}}kg{{m}^{2}}/s\] \[\lambda =\frac{6.63\times {{10}^{-34}}kg{{m}^{2}}{{S}^{-1}}}{(10\times {{10}^{-6}}kg)(100m/s)}\] \[6.63\times {{10}^{-31}}m\]You need to login to perform this action.
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