A) B<P<S<F
B) B<S<P<F
C) F<S<P<B
D) P<S<B<F
Correct Answer: B
Solution :
[b] B < S < P < F B and F lie in the 2nd period while P and S lie in the third period. Because of higher effective nuclear charge, Ai Hi of P and S are higher B than that of but lower than that of F. Among P and S, P has higher \[\Delta \]iHi due to exactly half filled configuration. Thus overall increasing order, is:You need to login to perform this action.
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