A) - 5J
B) - 10J
C) - 15J
D) - 20J
Correct Answer: A
Solution :
[a] AU = 0 [Cyclic process] \[W={{W}_{AB}}+{{W}_{BC}}+{{W}_{CA}}\] \[\Delta Q=\Delta U+W\] \[[\Delta U=0]\] \[\Delta Q=W\] \[5={{W}_{AB}}+{{W}_{BC}}+{{W}_{CA}}\] \[5=10[2-1]+2\times 0+{{W}_{CA}}\] \[5=10+0+{{W}_{CA}}\] \[{{W}_{CA}}=5-10=-5J\]You need to login to perform this action.
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