A) 150m/s
B) 27m/s
C) 450m/s
D) 250m/s
Correct Answer: A
Solution :
[a] \[{{V}_{PG}}\]= velocity of police with respect to ground \[{{V}_{TG}}\]= velocity of theif w.r.t. ground \[{{V}_{TP}}\] = velocity of theif w.r.t. police \[{{V}_{TP}}=[153-45]\times \frac{5}{18}=30m/s\] \[{{V}_{BC}}=180-30\] \[{{V}_{BC}}=150m/s\]You need to login to perform this action.
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