A) Propanal
B) Butanal
C) n-butyl alcohol
D) n-propyi alcohol
Correct Answer: D
Solution :
[d] n-propyi alcohol \[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow{P+{{I}_{2}}}\underset{(A)}{\mathop{\,C{{H}_{3}}C{{H}_{2}}I}}\,\xrightarrow[ether]{Mg}\] \[\underset{(B)}{\mathop{C{{H}_{3}}C{{H}_{2}}Mgl}}\,\xrightarrow{HCHO}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OMgl\] \[\begin{align} & \xrightarrow{{{H}_{2}}O}C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH \\ & n-propyl\,alcohol \\ \end{align}\]You need to login to perform this action.
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