A) \[2\pi m{{K}^{2}}{{r}^{2}}\]
B) \[m{{K}^{2}}{{r}^{2}}T\]
C) \[\frac{m{{K}^{2}}{{r}^{2}}{{t}^{5}}}{3}\]
D) zero
Correct Answer: B
Solution :
Given that, \[{{a}_{c}}=Kr{{t}^{2}}\] or \[\frac{{{\upsilon }^{2}}}{r}\] \[={{K}^{2}}r_{t}^{2}\] or \[\omega =krt\] ?..(i) Therefore, tangential acceleration. \[a=\frac{d\upsilon }{dt}=Kr\] or tangential force \[Ft=m{{a}_{t}}=mKr\] Only tangential force performs work Power \[={{F}_{t}}\upsilon =(mKr)\,(Krt)\] or power \[=m{{K}^{2}}{{r}^{2}}t\]You need to login to perform this action.
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