A) The body covers a distance 3m on the platform in the direction of motion of the platform
B) The body covers a distance 3m on the platform opposite to the direction of motion of platform before coming to rest.
C) The body covers a distance 6m on the platform in the direction of motion of the platform
D) The body covers a distance 6m on the platform opposite to the direction of motion of platform before coming to rest
Correct Answer: D
Solution :
Since \[M>>m,\] the velocity of M remains unchanged after m is placed on to it Acceleration of m, \[a=\frac{\mu mg}{m}=\mu g\] \[{{a}_{mM}}=a-0=a\] and initial relatives velocity \[{{V}_{mM}}=0-V=-V\] Hence, \[{{S}_{mM}}=\frac{V_{mM}^{2}}{2{{a}_{mM}}}=\frac{{{(6)}^{2}}}{2\times 0.3\times 10}=6m\]You need to login to perform this action.
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