A) \[0.5m\]
B) \[0.8m\]
C) \[1.0m\]
D) \[1.2m\]
Correct Answer: C
Solution :
From work - energy theorem Loss in potential energy= Gain in Kinetic energy Gives, \[u=\sqrt{2g({{h}_{1}}-{{h}_{2}})}\] \[\therefore \] Range, \[R=u\sqrt{\frac{2{{h}_{2}}}{g}}=2\sqrt{{{h}_{2}}({{h}_{1}}-{{h}_{2}})}\] \[\left( as,\,t=\sqrt{\frac{2H}{g}} \right)\] \[R=2\sqrt{0.5\times 0.5}=1.0m\]You need to login to perform this action.
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